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In a certain class, every student is either a boy or a girl.
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20 Nov 2017, 10:31
20 Nov 2017, 10:31
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Question Stats:
75% (01:00) correct
24% (00:48) wrong based on 141 sessions
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In a certain class, every student is either a boy or a girl. The boys constitute 5/13 of the students in the class.
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Kudos for correct solution.
Quantity A |
Quantity B |
The ratio of boys to girls in the class |
The fraction of the class that are girls |
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Kudos for correct solution.
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: In a certain class, every student is either a boy or a girl.
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27 Oct 2018, 10:31
27 Oct 2018, 10:31
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Carcass wrote:
In a certain class, every student is either a boy or a girl. The boys constitute \(\frac{5}{13}\) of the students in the class.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The ratio of boys to girls in the class |
The fraction of the class that are girls |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
If 5/13 of the students are boys, then the remaining 8/13 of the students are girls.
So, we might say, for every 5 boys there are, we have 8 girls.
In other words, the ratio of boys to girls = 5/8
So, we get:
QUANTITY A: 5/8
QUANTITY B: 8/13
One option is to convert these fractions to decimals (using long division or the onscreen calculator)
Here's what I'd do on test day:
Multiply both quantities by 8 to get:
QUANTITY A: 5
QUANTITY B: 64/13
Multiply both quantities by 13 to get:
QUANTITY A: 65
QUANTITY B: 64
Answer: A
Cheers,
Brent
General Discussion
Re: In a certain class, every student is either a boy or a girl.
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20 May 2018, 03:47
20 May 2018, 03:47
total no of kids are 13 as we can see that 5(boys)/13(total kids)
girl to boy ratio is 5/8
Girl to total ratio is 68/13
there we have 2 factions which we have to compare. In order to compair the faction one much make the base of teh faction as EQUIVALENT.
by multiplying 13 to entity A -- 5 and 8 to 13 we have 65/104
and option B by multiplying by 8 to both numerator and denominator we get 64/104
Option A is corrrect answer.
girl to boy ratio is 5/8
Girl to total ratio is 68/13
there we have 2 factions which we have to compare. In order to compair the faction one much make the base of teh faction as EQUIVALENT.
by multiplying 13 to entity A -- 5 and 8 to 13 we have 65/104
and option B by multiplying by 8 to both numerator and denominator we get 64/104
Option A is corrrect answer.
