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xyz < 0
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20 Oct 2017, 02:40
20 Oct 2017, 02:40
Expert Reply
00:00
Question Stats:
77% (00:45) correct
22% (00:44) wrong based on 66 sessions
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\(xyz < 0\)
Quantity A |
Quantity B |
\(x + y + z\) |
\(2x + 2y + 2z\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: xyz < 0
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20 Oct 2017, 06:17
20 Oct 2017, 06:17
The fact that xyz < 0 does not give enough information about the unknowns to be able to compare the two quantities. We just know that two of them should be positive and the other negative but nothing more. Given that we can't compare the quantities answer is D!
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xyz < 0
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31 May 2020, 06:07
31 May 2020, 06:07
1
Carcass wrote:
\(xyz < 0\)
Quantity A |
Quantity B |
\(x + y + z\) |
\(2x + 2y + 2z\) |
Let's test some possible values of x, y and z
case i: Since \(xyz < 0\), it could be the case that \(x=1\), \(y=1\) and \(z=-1\)
We get:
Quantity A: \(x + y + z = 1 + 1 + (-1) = 1\)
Quantity B: \(2(1) + 2(1) + 2(-1) = 2\)
In this case, Quantity B is greater
case -i: Since \(xyz < 0\), it could be the case that \(x=-1\), \(y=-1\) and \(z=-1\)
We get:
Quantity A: \(x + y + z = (-1) + (-1) + (-1) = -3\)
Quantity B: \(2(-1) + 2(-1) + 2(-1) = -6\)
In this case, Quantity A is greater
Answer: D
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