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11<y<17
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01 Mar 2019, 06:58
01 Mar 2019, 06:58
Expert Reply
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Question Stats:
76% (00:45) correct
23% (01:05) wrong based on 30 sessions
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11<y<17
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Diagnostic #8
Quantity A |
Quantity B |
\(\frac{y}{y+17}\) |
\(\frac{y}{y+11}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Diagnostic #8
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Re: 11<y<17
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01 Mar 2019, 08:01
01 Mar 2019, 08:01
2
chetan2u wrote:
11<y<17
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Diagnostic #8
Quantity A |
Quantity B |
\(\frac{y}{y+17}\) |
\(\frac{y}{y+11}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Diagnostic #8
We can solve this question using matching operations
Given:
Quantity A: y/(y + 17)
Quantity B: y/(y + 11)
Since y is POSITIVE, we can safely divide both quantities by y to get:
Quantity A: 1/(y + 17)
Quantity B: 1/(y + 11)
Since y is POSITIVE, we know that (y + 17) is POSITIVE, so we can safely multiply both quantities by (y + 17) to get:
Quantity A: 1
Quantity B: (y + 17)/(y + 11)
Likewise, we can safely multiply both quantities by (y + 11) to get:
Quantity A: y + 11
Quantity B: y + 17
Subtract y from both quantities to get:
Quantity A: 11
Quantity B: 17
Answer: B
Cheers,
Brent
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Re: 11<y<17
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01 Mar 2019, 08:11
01 Mar 2019, 08:11
Expert Reply
chetan2u wrote:
11<y<17
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Diagnostic #8
Quantity A |
Quantity B |
\(\frac{y}{y+17}\) |
\(\frac{y}{y+11}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Diagnostic #8
Thanks Brent.
The other way would be.
The numerator of both A and B is the same, that is y. But the denominator of A will be greater than that of B, as we are adding 17 to y as compared to 11 in A.
thus, A will be lesser than B.
B
