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r > zero
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04 Feb 2018, 15:07
04 Feb 2018, 15:07
Expert Reply
00:00
Question Stats:
95% (00:27) correct
5% (00:28) wrong based on 80 sessions
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\(r > 0\)
Quantity A |
Quantity B |
\(\frac{7}{r+8}\) |
\(\frac{7}{r}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Kudos for the right solution and explanation
Sherpa Prep Representative
Joined: 15 Jan 2018
Posts: 147
Given Kudos: 0
Re: r > zero
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Updated on: 08 Feb 2018, 08:43
Updated on: 08 Feb 2018, 08:43
3
Expert Reply
The easiest way to solve this one is to cross-multiply and then subtract the common values. We're allowed to do this, btw, because we've been told r is positive. If we hadn't been told anything about whether r is positive or negative, we wouldn't be able to use this technique. See attached picture. Since the simplest version of this problem is 0 vs 56, we can see that Quantity B is bigger.
Attachments
IMG_20180208_113654.jpg [ 39.25 KiB | Viewed 6168 times ]
Originally posted by SherpaPrep on 04 Feb 2018, 20:32.
Last edited by SherpaPrep on 08 Feb 2018, 08:43, edited 2 times in total.
Last edited by SherpaPrep on 08 Feb 2018, 08:43, edited 2 times in total.
Re: r > zero
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05 Feb 2018, 02:37
05 Feb 2018, 02:37
1
Carcass wrote:
\(r > 0\)
Quantity A |
Quantity B |
\(\frac{7}{r+8}\) |
\(\frac{7}{r}\) |
Here given r>0
So the value of r has to be positive. It can be either integer or a fraction.
Now we know if denominator > numerator then the value will be always less than 1.
Now compare QTY A and QTY b,
we can see that QTY A has denominator r+8, and the denominator of QTY B is r, so what ever the value of r (i.e integer or fraction) the value of QTY B > QTY A
