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For all nonzero integers l and m, let the operation § be def
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26 Mar 2018, 15:51
26 Mar 2018, 15:51
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83% (00:39) correct
16% (01:38) wrong based on 30 sessions
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For all nonzero integers l and m, let the operation § be defined by l § m \(= - \mid \frac{l+m}{lm} \mid\).
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
3§ \(\frac{3}{2}\) |
-1 |
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Drill 2
Question: 3
Page: 549
Question: 3
Page: 549
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Joined: 15 Jan 2018
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Re: For all nonzero integers l and m, let the operation § be def
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04 Apr 2018, 04:18
04 Apr 2018, 04:18
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Expert Reply
In a fake function problem like this we simply need to follow their instructions. In this case, add the terms on either side of the §, then multiply them and divide the former result by the latter result. Then get its absolute value and slap a minus sign on the whole thing. Let's do it.
In quantity A, for the numerator:
3 + 3/2 = 9/2
For the denominator:
3x(3/2) = 9/2
If we divide 3/2 by 3/2 obviously we'll get 1. Since -|1| = -1, the answer must be C.
In quantity A, for the numerator:
3 + 3/2 = 9/2
For the denominator:
3x(3/2) = 9/2
If we divide 3/2 by 3/2 obviously we'll get 1. Since -|1| = -1, the answer must be C.
Re: For all nonzero integers l and m, let the operation § be def
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04 Apr 2018, 15:59
04 Apr 2018, 15:59
1
Expert Reply
Explanation
When a problem gives you a relationship signified by an unfamiliar symbol: Just plug in the given values into the given “function” and solve.
If l § m=\(-|\frac{l+m}{lm}|\) then 3 §\(\frac{3}{2}\)=\(-|\frac{3+ 1.5}{3 \times 1.5}|=-1\).
The quantities are equal, so select choice (C).
When a problem gives you a relationship signified by an unfamiliar symbol: Just plug in the given values into the given “function” and solve.
If l § m=\(-|\frac{l+m}{lm}|\) then 3 §\(\frac{3}{2}\)=\(-|\frac{3+ 1.5}{3 \times 1.5}|=-1\).
The quantities are equal, so select choice (C).
