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f (x) = (a x ^n)
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11 Dec 2023, 00:10
11 Dec 2023, 00:10
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25% (01:55) correct
75% (01:33) wrong based on 20 sessions
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\(f (x) = (a − x^n)^{\frac{1}{n}}\) and \(f (1) = p\).
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(f(p)\) |
0 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Free Materials for the GRE General Exam - Where to get it!!
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f (x) = (a x ^n)
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12 Dec 2023, 13:42
12 Dec 2023, 13:42
2
\(f(1) = (a-1^n)^\frac{1}{n} = p\)
\([(a-1^n)^\frac{1}{n}]^n = p^n\)
\((a-1^n) = p^n\)
\(f(p) = (a-p^n)^\frac{1}{n}\)
Substitute in \(p^n = (a-1^n)\)
\(= (a-((a-1^n)))^\frac{1}{n}\)
\(= (1^n)^\frac{1}{n}\)
\(f(p)=1\)
\([(a-1^n)^\frac{1}{n}]^n = p^n\)
\((a-1^n) = p^n\)
\(f(p) = (a-p^n)^\frac{1}{n}\)
Substitute in \(p^n = (a-1^n)\)
\(= (a-((a-1^n)))^\frac{1}{n}\)
\(= (1^n)^\frac{1}{n}\)
\(f(p)=1\)
Re: f (x) = (a x ^n)
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28 Dec 2025, 01:28
28 Dec 2025, 01:28
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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