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(141)2 – (28)2
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15 Apr 2018, 04:36
15 Apr 2018, 04:36
Expert Reply
00:00
Question Stats:
88% (00:36) correct
12% (00:37) wrong based on 25 sessions
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Quantity A |
Quantity B |
\((141)^2 - (28)^2\) |
\((141-28)^2\) |
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Drill 1
Question: 6
Page: 511
Question: 6
Page: 511
Re: (141)2 – (28)2
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22 Apr 2018, 12:14
22 Apr 2018, 12:14
Expert Reply
Explanation
Don’t do the arithmetic! These are common quadratic patterns.
It’s not important that x = 141 and y = 28;
Quantity A is \(x^2 - y^2 = (x + y)(x - y)\), and
Quantity B is \((x - y)(x - y).\)
Since (x – y) is a positive number, you can simply compare the remaining factors after it is removed from both quantities. Since x and y are positive, (x + y) is greater than the
remaining (x – y) in Quantity B, and the answer is choice (A).
Don’t do the arithmetic! These are common quadratic patterns.
It’s not important that x = 141 and y = 28;
Quantity A is \(x^2 - y^2 = (x + y)(x - y)\), and
Quantity B is \((x - y)(x - y).\)
Since (x – y) is a positive number, you can simply compare the remaining factors after it is removed from both quantities. Since x and y are positive, (x + y) is greater than the
remaining (x – y) in Quantity B, and the answer is choice (A).
gmatclubot
Re: (141)2 – (28)2 [#permalink]
22 Apr 2018, 12:14
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