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a > 0 || (–a – 10)(10 + a) || 10
[#permalink]
06 Apr 2018, 15:30
06 Apr 2018, 15:30
Expert Reply
00:00
Question Stats:
80% (00:45) correct
20% (00:47) wrong based on 30 sessions
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\(a > 0\)
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\((-a - 10)(10 + a)\) |
10 |
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Drill 1
Question: 5
Page: 507-508
Question: 5
Page: 507-508
Re: a > 0 || (–a – 10)(10 + a) || 10
[#permalink]
15 Apr 2018, 05:29
15 Apr 2018, 05:29
Expert Reply
Explanation
Quantity A to find \(-10a - a^2 - 100 - 10a\), or \(-a2 - 20a - 100\).
Anything other than zero to an even power is positive, so \(-a^2\) is negative.
A negative number minus a positive number (20a) will remain negative.
A negative minus 100 will be even more negative.
So, Quantity A must be negative, and it must be less than Quantity B. The answer is choice (B).
Alternatively, plugging in a few positive values for a will give you, in the parentheses: (negative) times (positive) = negative for Quantity A, except if a = 10, which yields 0 for Quantity A. But Quantity A is still less than Quantity B.
Quantity A to find \(-10a - a^2 - 100 - 10a\), or \(-a2 - 20a - 100\).
Anything other than zero to an even power is positive, so \(-a^2\) is negative.
A negative number minus a positive number (20a) will remain negative.
A negative minus 100 will be even more negative.
So, Quantity A must be negative, and it must be less than Quantity B. The answer is choice (B).
Alternatively, plugging in a few positive values for a will give you, in the parentheses: (negative) times (positive) = negative for Quantity A, except if a = 10, which yields 0 for Quantity A. But Quantity A is still less than Quantity B.
gmatclubot
Re: a > 0 || (–a – 10)(10 + a) || 10 [#permalink]
15 Apr 2018, 05:29
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