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For the positive integers a, b, c, and d, a is half of b, wh
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20 May 2018, 16:49
20 May 2018, 16:49
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For the positive integers a, b, c, and d, a is half of b, which is one-third of c. The value of d is triple that of c.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(\frac{a+b}{c}\) |
\(\frac{a+b+c}{d}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: For the positive integers a, b, c, and d, a is half of b, wh
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27 May 2018, 19:11
27 May 2018, 19:11
sandy wrote:
For the positive integers a, b, c, and d, a is half of b, which is one-third of c. The value of d is triple that of c.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(\frac{a+b}{c}\) |
\(\frac{a+b+c}{d}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Please provide the solution.
Re: For the positive integers a, b, c, and d, a is half of b, wh
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28 May 2018, 02:04
28 May 2018, 02:04
2
first, translate all the words into mathematical equations. so that will be:
2a=b
3b=c
d=3c
the next step is to substitute all the equations we've got. C is equal to 3b (c=3b), and we know that b = 2a. So we can write c= 3b= 3(2a)= 6a.
in other words, we state all the variable in terms of one variable (in my case, I chose variable a cause it's easy)
it will be like this:
b= 2a
c= 3b= 6a
d= 3c= 18a
the final step is to write the quantities (A and B) in terms of variable a and do the math. you'll see that quantity A and B are equal: both final result is 1/2
hope this helps
2a=b
3b=c
d=3c
the next step is to substitute all the equations we've got. C is equal to 3b (c=3b), and we know that b = 2a. So we can write c= 3b= 3(2a)= 6a.
in other words, we state all the variable in terms of one variable (in my case, I chose variable a cause it's easy)
it will be like this:
b= 2a
c= 3b= 6a
d= 3c= 18a
the final step is to write the quantities (A and B) in terms of variable a and do the math. you'll see that quantity A and B are equal: both final result is 1/2
hope this helps
