GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 28Live Online Class with Top GRE Expert Mike Butville
08:00 PM EDT
-10:00 PM EDT
Top scores are possible when you enroll in a powerful GRE course, taught live online + 6 months access to TTP GRE OnDemand video courses included! Class starts Mon/Wed Sept. 28, 2026 - Dec. 9, 2026, 8:00pm-10:00pm EST
An item’s price was discounted by 16%. Later, the discounted
[#permalink]
10 Jun 2018, 03:58
10 Jun 2018, 03:58
Expert Reply
1
Bookmarks
00:00
Question Stats:
94% (00:35) correct
5% (00:07) wrong based on 76 sessions
Hide Show timer Statistics
An item’s price was discounted by 16%. Later, the discounted price was increased by 16%.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The original price |
The price after the discount and increase |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: An item’s price was discounted by 16%. Later, the discounted
[#permalink]
13 Jun 2018, 16:34
13 Jun 2018, 16:34
Expert Reply
Explanation
The problem doesn’t indicate any specific values, so pick a smart number. Because this is a percent problem, call the original price $100. Quantity A equals $100.
Decreasing a value by 16% is the same as taking (100 – 16)% = 84% of the number: so (0.84)(100) = $84.
To increase the value by 16%, take 116% of the number, or multiply by 1.16: (1.16)(84) = $97.44.
Quantity A is greater.
The problem doesn’t indicate any specific values, so pick a smart number. Because this is a percent problem, call the original price $100. Quantity A equals $100.
Decreasing a value by 16% is the same as taking (100 – 16)% = 84% of the number: so (0.84)(100) = $84.
To increase the value by 16%, take 116% of the number, or multiply by 1.16: (1.16)(84) = $97.44.
Quantity A is greater.
Re: An item’s price was discounted by 16%. Later, the discounted
[#permalink]
13 Jun 2018, 17:27
13 Jun 2018, 17:27
Assume the original price = P
Quantity A = P
Quantity B = P*(1-16%)*(1+16%) = P(1-0.16^2) < P = A
--> A > B
Keys: A
Quantity A = P
Quantity B = P*(1-16%)*(1+16%) = P(1-0.16^2) < P = A
--> A > B
Keys: A
