The question is not about combination it is about permutation

Let us say that 3 types of lunch (L1, L2 and L3) are available and 2 people have are ordering

In case if they order different dishes

There are three options for first person and 2 options for the second person. So 6 orders are possible.

3p2 =6 while 3c2 =3 .

So the answers will be

10p2 = 90

10p3 = 720

10p4 = 5040

how to do the math?

Exactly the way the mods explained above. It is a combination problem

here a good start https://gmat.economist.com/gmat-advice/ ... gmat-quant

Regards

I don't think order does matter here. If I buy one pizza and one cheesecake, then it is same as ordering one cheesecake and one pizza. They are making an order together, not individually.

This is a badly worded question. What does "She brings at least 1 member of her family to dinner for lunch every day. The none offers 10 lunch specials" even mean?! The none offers? 1 member of her family to dinner for lunch?!

Request moderators to edit this.

I think is better to move on from this question or questions like this.

if we edit it without having in hand the question as it was originally maybe we could create even more confusion.

will see what GreenLight could say regarding this one

Regards

It's a bad question for a two reasons.

First, we aren't told whether Sandy eats at the diner. All we know is that she brings 1, 2, or three people to the diner. This might seem like small potatoes, but the test-makers would never allow such ambiguity in a question.

Second (and more importantly), if answer choice A (45) is one of the official answers, then this means Sandy having a hamburger and her husband having kale is the SAME as Sandy having kale and her husband having a hamburger. Those two outcomes seem very different to me.

Thank you Sir you came to rescue us

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