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Suppose M = |15x +25y|. x and y are different integers. Which of the f
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16 Sep 2024, 23:57
16 Sep 2024, 23:57
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Question Stats:
50% (01:35) correct
50% (01:07) wrong based on 20 sessions
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Suppose \(M = |15x +25y|\). x and y are different integers. Which of the following can be possible values of M?
A. 10
B. 0
C. 2
D. 5
A. 10
B. 0
C. 2
D. 5
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Re: Suppose M = |15x +25y|. x and y are different integers. Which of the f
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20 Dec 2024, 11:08
20 Dec 2024, 11:08
Expert Reply
We have $\(M=|15 x+25 y|\)$, where $\(x\)$ and $\(y\)$ are different integers, which is an absolute value of addition/subtraction of $\(15 x\)$ and $\(25 y\)$ i.e. multiples of 5 .
So the value of M should be nothing but the addition or subtraction of multiples of 5 .
Thus the value of M can be a multiple of 5 only.
Hence the values of $\(M\)$ can be (A), (B) \& (D) only.
So the value of M should be nothing but the addition or subtraction of multiples of 5 .
Thus the value of M can be a multiple of 5 only.
Hence the values of $\(M\)$ can be (A), (B) \& (D) only.
Re: Suppose M = |15x +25y|. x and y are different integers. Which of the f
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21 Sep 2025, 00:08
21 Sep 2025, 00:08
|15x + 25y| = 5|3x + 5y|
now 3x+5y = 2
if M = 10
this is true for x = -1 , y = 1
now 3x + 5y = 0
if M = 0
this is true if x = (-5/3)y which are not integers
now 3x + 5y = 2/5
if M = 2
which is possible only if x and y are in fractions
and finally 3x + 5y = 1
if M = 5
this is true if x = 2 and y = -1
so options A and D alone are correct
Carcass
now 3x+5y = 2
if M = 10
this is true for x = -1 , y = 1
now 3x + 5y = 0
if M = 0
this is true if x = (-5/3)y which are not integers
now 3x + 5y = 2/5
if M = 2
which is possible only if x and y are in fractions
and finally 3x + 5y = 1
if M = 5
this is true if x = 2 and y = -1
so options A and D alone are correct
Carcass
