GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
For what values of x are both the mean (average) and the median weekly
[#permalink]
09 Jun 2021, 00:20
09 Jun 2021, 00:20
2
Expert Reply
7
Bookmarks
00:00
Question Stats:
37% (03:12) correct
62% (02:20) wrong based on 72 sessions
Hide Show timer Statistics
The table shows the weekly spending of a small business on office supplies.
GRE table.png [ 6.94 KiB | Viewed 4504 times ]
For what values of x are both the mean (average) and the median weekly spending for the entire period between 60 and 70 dollars?
Indicate all that apply.
A. 65
B. 72
C. 80
D. 83
E. 89
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Attachment:
GRE table.png [ 6.94 KiB | Viewed 4504 times ]
For what values of x are both the mean (average) and the median weekly spending for the entire period between 60 and 70 dollars?
Indicate all that apply.
A. 65
B. 72
C. 80
D. 83
E. 89
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
For what values of x are both the mean (average) and the median weekly
[#permalink]
09 Jun 2021, 07:40
09 Jun 2021, 07:40
4
2
Bookmarks
Dollars spent : 0 , 12 , 54 , x , 88 , 185
We need such x, that mean & median is between 60 & 70
Mean = \(\frac{x + 339}{6}\)
\(60 < \frac{x + 339}{6} < 70\)
\(360 < x + 339 < 420\)
\(21 < x < 81\)
We now have three possibilities. \(65 , 72 , 80\)
Median = \(\frac{x + 54}{2}\)
\(60 < \frac{x + 54}{2} < 70\)
\(120 < x +54 < 140\)
\(66 < x < 86\)
72 , 80
Answer B C
We need such x, that mean & median is between 60 & 70
Mean = \(\frac{x + 339}{6}\)
\(60 < \frac{x + 339}{6} < 70\)
\(360 < x + 339 < 420\)
\(21 < x < 81\)
We now have three possibilities. \(65 , 72 , 80\)
Median = \(\frac{x + 54}{2}\)
\(60 < \frac{x + 54}{2} < 70\)
\(120 < x +54 < 140\)
\(66 < x < 86\)
72 , 80
Answer B C
General Discussion
Re: For what values of x are both the mean (average) and the median weekly
[#permalink]
13 Nov 2025, 09:57
13 Nov 2025, 09:57
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
