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The average measure of the interior angles of an n-sided polygon is di
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04 Jan 2023, 08:11
04 Jan 2023, 08:11
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62% (01:42) correct
37% (01:54) wrong based on 16 sessions
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The average measure of the interior angles of an n-sided polygon is divisible by 10. For which values of n could this be true?
Indicate all such values.
A. 4
B. 5
C. 6
D. 8
E. 9
F. 10
Indicate all such values.
A. 4
B. 5
C. 6
D. 8
E. 9
F. 10
Re: The average measure of the interior angles of an n-sided polygon is di
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04 Jan 2023, 09:14
04 Jan 2023, 09:14
Expert Reply
OE
Since the sum of the interior angles of an n-sided polygon must equal (n - 2) x 180°, the average of the angles will equal:
(n-2)*180/n=360/n
Since 180 is divisible by 10, you need only evaluate whether 360/n is divisible by 10 for each answer choice
Since the sum of the interior angles of an n-sided polygon must equal (n - 2) x 180°, the average of the angles will equal:
(n-2)*180/n=360/n
Since 180 is divisible by 10, you need only evaluate whether 360/n is divisible by 10 for each answer choice
Re: The average measure of the interior angles of an n-sided polygon is di
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28 Dec 2023, 13:32
28 Dec 2023, 13:32
"(n-2)*180/n=360/n"
I don't understand this.
So I also don't understand "Since 180 is divisible by 10, you need only evaluate whether 360/n is divisible by 10 for each answer choice"
I don't understand this.
So I also don't understand "Since 180 is divisible by 10, you need only evaluate whether 360/n is divisible by 10 for each answer choice"
