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If a>0 and b>0, which of the following is equivalent
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Updated on: 24 Jun 2024, 00:49
Updated on: 24 Jun 2024, 00:49
Expert Reply
00:00
Question Stats:
100% (00:25) correct
0% (00:00) wrong based on 3 sessions
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If a>0 and b>0, which of the following is equivalent to \(\frac{a}{b} \sqrt{(\frac{b}{a})^2}\)
A. \(1\)
B. \(\dfrac{1}{\sqrt{b}}\)
C. \(\sqrt{\frac{1}{b}}\)
D. \(\sqrt{\frac{a}{b}}\)
A. \(1\)
B. \(\dfrac{1}{\sqrt{b}}\)
C. \(\sqrt{\frac{1}{b}}\)
D. \(\sqrt{\frac{a}{b}}\)
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Shorter GRE - Preparing for the Quantitative Reasoning Measure
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Re: If a>0 and b>0, which of the following is equivalent
[#permalink]
23 Jun 2024, 23:37
23 Jun 2024, 23:37
1
IS the solution not equal to 1 , then only A should be correct right? How is B,C ,D correct? Can someone explain
Re: If a>0 and b>0, which of the following is equivalent
[#permalink]
24 Jun 2024, 00:48
24 Jun 2024, 00:48
1
Expert Reply
Fixed the question.
The book reported wrongly
\(\frac{a}{b} \sqrt{(\frac{b}{a})^2}\) \(= \frac{a}{b}[(\frac{b}{a})^2]^{\frac{1}{2}}\) \(= \frac{a}{b} \times \frac{b}{a }=1\)
The book reported wrongly
\(\frac{a}{b} \sqrt{(\frac{b}{a})^2}\) \(= \frac{a}{b}[(\frac{b}{a})^2]^{\frac{1}{2}}\) \(= \frac{a}{b} \times \frac{b}{a }=1\)
