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In a set of five consecutive integers, which of the followin
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08 Dec 2017, 20:54
08 Dec 2017, 20:54
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Expert Reply
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Question Stats:
53% (01:08) correct
46% (02:19) wrong based on 13 sessions
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In a set of five consecutive integers, which of the following must change the average of the set without changing its median ?
A. Multiplying each of the numbers in the set by 6.
B. Adding 10 to each of the numbers in the set.
C. Subtracting 3.5 from each of the numbers in the set.
D. Adding 8.2 to the 2 largest numbers and subtracting 8.2 from the 3 smallest numbers in the set.
E. Adding .5 to the 2 largest and to the 2 smallest numbers in the set.
F. Dividing each of the numbers in the set by 2.
G. It’s not possible to change the average of the set without changing its median.
A. Multiplying each of the numbers in the set by 6.
B. Adding 10 to each of the numbers in the set.
C. Subtracting 3.5 from each of the numbers in the set.
D. Adding 8.2 to the 2 largest numbers and subtracting 8.2 from the 3 smallest numbers in the set.
E. Adding .5 to the 2 largest and to the 2 smallest numbers in the set.
F. Dividing each of the numbers in the set by 2.
G. It’s not possible to change the average of the set without changing its median.
Drill 4
Question: 4
Page: 531
Question: 4
Page: 531
Re: In a set of five consecutive integers, which of the followin
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29 Dec 2017, 16:24
29 Dec 2017, 16:24
Expert Reply
Explanation
Start by plugging in a set of consecutive integers that encompasses the full spectrum of integers, such as −2, −1, 0, 1, 2. The average and median of the set are both 0.
In any set of consecutive integers, the average will always equal the median. Performing the operations in choices (A), (B), (C), and (F) results in sets of numbers that are still consecutive.
Thus, while in choices (B), (C), and (F) the averages change, the medians also change to those same values.
Eliminate choices (B), (C), and (F). In choice (A), neither the average nor the median changes, so you can eliminate it as well. For choice (D), the new average is −1.64 and the new median is −8.2. Again, both values change, so you can eliminate choice (D). In choice (E), the new average is .4, but the median hasn’t changed; choice (E) works. You can eliminate choice (G) based on the other calculations, and the only correct answer is choice E.
Start by plugging in a set of consecutive integers that encompasses the full spectrum of integers, such as −2, −1, 0, 1, 2. The average and median of the set are both 0.
In any set of consecutive integers, the average will always equal the median. Performing the operations in choices (A), (B), (C), and (F) results in sets of numbers that are still consecutive.
Thus, while in choices (B), (C), and (F) the averages change, the medians also change to those same values.
Eliminate choices (B), (C), and (F). In choice (A), neither the average nor the median changes, so you can eliminate it as well. For choice (D), the new average is −1.64 and the new median is −8.2. Again, both values change, so you can eliminate choice (D). In choice (E), the new average is .4, but the median hasn’t changed; choice (E) works. You can eliminate choice (G) based on the other calculations, and the only correct answer is choice E.
Re: In a set of five consecutive integers, which of the followin
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25 Aug 2021, 06:17
25 Aug 2021, 06:17
Didnt understand the question
