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Mark can take three friends with him on a vacation and is
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30 Dec 2017, 14:09
30 Dec 2017, 14:09
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Question Stats:
30% (00:59) correct
69% (01:18) wrong based on 36 sessions
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Mark can take three friends with him on a vacation and is listing the possible combinations of friends. If he has five friends to choose from and is numbering each possible combination sequentially beginning with 1, which of the following numbers will appear on his list of combinations?
Indicate all possible values.
A. 2
B. 10
C. 15
D. 24
E. 60
F. 120
Indicate all possible values.
A. 2
B. 10
C. 15
D. 24
E. 60
F. 120
Drill 2
Question: 9
Page: 564
Question: 9
Page: 564
Re: Mark can take three friends with him on a vacation and is
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12 Jan 2018, 15:27
12 Jan 2018, 15:27
2
Expert Reply
Explanation
The order of friends doesn’t matter.
There are five friends to choose from for three spots, so the top of your fraction should read: 5*4*3, and to correct for the order of friends not mattering, the bottom of your fraction should be: 321.
\(\frac{5 \times 4 \times 3}{3 \times 2 \times 1}= 10\).
Since he is numbering possibilities sequentially, the numbers 1 through 10 will be on the list, making choices (A) and (B) correct.
The order of friends doesn’t matter.
There are five friends to choose from for three spots, so the top of your fraction should read: 5*4*3, and to correct for the order of friends not mattering, the bottom of your fraction should be: 321.
\(\frac{5 \times 4 \times 3}{3 \times 2 \times 1}= 10\).
Since he is numbering possibilities sequentially, the numbers 1 through 10 will be on the list, making choices (A) and (B) correct.
Re: Mark can take three friends with him on a vacation and is
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06 May 2020, 11:17
06 May 2020, 11:17
sandy wrote:
Explanation
The order of friends doesn’t matter.
There are five friends to choose from for three spots, so the top of your fraction should read: 5*4*3, and to correct for the order of friends not mattering, the bottom of your fraction should be: 321.
\(\frac{5 \times 4 \times 3}{3 \times 2 \times 1}= 10\).
Since he is numbering possibilities sequentially, the numbers 1 through 10 will be on the list, making choices (A) and (B) correct.
The order of friends doesn’t matter.
There are five friends to choose from for three spots, so the top of your fraction should read: 5*4*3, and to correct for the order of friends not mattering, the bottom of your fraction should be: 321.
\(\frac{5 \times 4 \times 3}{3 \times 2 \times 1}= 10\).
Since he is numbering possibilities sequentially, the numbers 1 through 10 will be on the list, making choices (A) and (B) correct.
what does it mean that he is listing the combinations sequentially? I get that there are a possible 10 different combinations, but I do not understand the wording of "numbering each possible combination sequentially beginning with 1". Thank you for your help!
