GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 17Live Online Classes with Top GRE Expert Rich Zwelling
08:00 PM EST
-10:00 PM EST
Get live instruction from a top-scoring, industry-recognized GRE teachers + 6 months of access to TTP Self-Study included! Tues/Thur Sept 7, 2026---Feb. 2, 2027, 1:00pm-3:00pm EST
Dec 14Live Online Classes with Top GRE Expert Michael Butville
08:00 PM EST
-10:00 PM EST
Get live instruction from a top-scoring, industry-recognized GRE teachers + 6 months of access to TTP Self-Study included! Mon/Wed Dec. 14, 2026---Feb. 22, 2027, 8:00pm-10:00pm EST
If |3x + 7| ≥ 2x + 12, then which of the following is true?
[#permalink]
08 Aug 2018, 16:28
08 Aug 2018, 16:28
2
Expert Reply
3
Bookmarks
00:00
Question Stats:
61% (01:23) correct
38% (01:49) wrong based on 187 sessions
Hide Show timer Statistics
If \(|3x + 7| ≥ 2x + 12\), then which of the following is true?
A. \(x \leq \frac{-19}{5}\)
B. \(x \geq \frac{-19}{5}\)
C. \(x \geq 5\)
D. \(x \leq \frac{-19}{5}\) or \(x \geq 5\)
E. \(\frac{-19}{5} \leq x \leq 5\)
Kudos for R.A.E
A. \(x \leq \frac{-19}{5}\)
B. \(x \geq \frac{-19}{5}\)
C. \(x \geq 5\)
D. \(x \leq \frac{-19}{5}\) or \(x \geq 5\)
E. \(\frac{-19}{5} \leq x \leq 5\)
Kudos for R.A.E
Re: If |3x + 7| ≥ 2x + 12, then which of the following is true?
[#permalink]
09 Aug 2018, 14:06
09 Aug 2018, 14:06
3
2
Bookmarks
Carcass wrote:
If \(|3x + 7| ≥ 2x + 12\), then which of the following is true?
A. \(x \leq \frac{-19}{5}\)
B. \(x \geq \frac{-19}{5}\)
C. \(x \geq 5\)
D. \(x \leq \frac{-19}{5}\) or \(x \geq 5\)
E. \(\frac{-19}{5} \leq x \leq 5\)
Kudos for R.A.E
A. \(x \leq \frac{-19}{5}\)
B. \(x \geq \frac{-19}{5}\)
C. \(x \geq 5\)
D. \(x \leq \frac{-19}{5}\) or \(x \geq 5\)
E. \(\frac{-19}{5} \leq x \leq 5\)
Kudos for R.A.E
For absolute value there will be 2 cases all time.
Case 1 : when 3x + 7 is positive.
\(3x + 7 \geq2x + 12\)
\(x \geq5\)
Case 2: When 3x + 7 is negative.
\(-3x - 7 \geq2x + 12\)
\(x \leq-19/5.\)
The best answer is D.
General Discussion
Re: If |3x + 7| ≥ 2x + 12, then which of the following is true?
[#permalink]
04 Mar 2020, 14:34
04 Mar 2020, 14:34
For some reason I keep getting X less than or equal to -19/5 when I make the right side negative and add the variables to get +5. Why does thi shappen?
