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If p is a positive integer and 10p 96 is an integer, then the minimum
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21 Sep 2021, 20:59
21 Sep 2021, 20:59
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Question Stats:
46% (01:01) correct
53% (00:51) wrong based on 13 sessions
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If p is a positive integer and \(\frac{10p}{96}\) is an integer, then the minimum number of prime factors p could have is
(A) One
(B) Two
(C) Three
(D) Four
(E) Five
(A) One
(B) Two
(C) Three
(D) Four
(E) Five
Re: If p is a positive integer and 10p 96 is an integer, then the minimum
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21 Sep 2021, 21:16
21 Sep 2021, 21:16
1
As it asks for minimum prime factors, consider p = 96 ( least multiple to go in 96) Also 10p/ 96 is an integer.
Hence 10 * 96 / 96 = 10 . Prime factors of 10 include 2 and 5
Hence B
Hence 10 * 96 / 96 = 10 . Prime factors of 10 include 2 and 5
Hence B
gmatclubot
Re: If p is a positive integer and 10p 96 is an integer, then the minimum [#permalink]
21 Sep 2021, 21:16
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