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In the figure shown, if ∠A = 60°, ∠B = ∠C, and BC = 20, then
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03 Oct 2018, 07:48
03 Oct 2018, 07:48
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100% (00:26) correct
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#GREpracticequestion In the figure shown, if ∠A = 60.jpg [ 12.53 KiB | Viewed 3455 times ]
In the figure shown, if ∠A = 60°, ∠B = ∠C, and BC = 20, then AB =
(A) \(20\)
(B) \(10 \sqrt{2}\)
(C) \(10 \sqrt{3}\)
(D) \(20 \sqrt{2}\)
(E) \(20 \sqrt{3}\)
Re: In the figure shown, if ∠A = 60°, ∠B = ∠C, and BC = 20, then
[#permalink]
04 Oct 2018, 08:39
04 Oct 2018, 08:39
1
Two angles are equal and the third angle of a triangle = 60 degree
so it must be that the other two angles also equal 60 degrees. Therefore this is an equilateral triangle.
In a equilateral triangle all sides are equal. Therefore if one side = 20 then all sides equal to 20
so it must be that the other two angles also equal 60 degrees. Therefore this is an equilateral triangle.
In a equilateral triangle all sides are equal. Therefore if one side = 20 then all sides equal to 20
gmatclubot
Re: In the figure shown, if ∠A = 60°, ∠B = ∠C, and BC = 20, then [#permalink]
04 Oct 2018, 08:39
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