GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
In the figure above, the circle is inscribed in a square tha
[#permalink]
06 Oct 2018, 15:12
06 Oct 2018, 15:12
Expert Reply
00:00
Question Stats:
77% (01:05) correct
22% (00:51) wrong based on 40 sessions
Hide Show timer Statistics
Attachment:
Capture.JPG [ 12.52 KiB | Viewed 2884 times ]
In the figure above, the circle is inscribed in a square that has an area of 50. What is the area of the circle?
(A) \(\frac{25\pi}{4}\)
(B) \(\frac{25\pi}{2}\)
(C) \(25\pi\)
(D) \(50\pi\)
(E) \(\frac{625\pi}{16}\)
Re: In the figure above, the circle is inscribed in a square tha
[#permalink]
15 Oct 2018, 04:29
15 Oct 2018, 04:29
area of the circle = 50
area of the circle = \(side^2\)
\(s^2\) = 50
s =\(5\sqrt{2}\)
This is also the diameter of the circle
therefore, radius = \(5/\sqrt{2}\)
area of the circle = \(25\pi/2\)
area of the circle = \(side^2\)
\(s^2\) = 50
s =\(5\sqrt{2}\)
This is also the diameter of the circle
therefore, radius = \(5/\sqrt{2}\)
area of the circle = \(25\pi/2\)
In the figure above, the circle is inscribed in a square tha
[#permalink]
04 Jan 2024, 22:45
04 Jan 2024, 22:45
The area of the square is \(50\).
The length of its side is\( \sqrt{50}\) = diameter of the inscribed circle.
The radius of the inscribed circle = \(\frac{\sqrt{50}}{2}\)
\(\text{Area of the circle} = \pi \times r^2 = \pi \times (\frac{\sqrt{50}}{2})^2 = \pi \frac{50}{4} = \frac{25 \pi}{2}\)
The answer is Choice B
The length of its side is\( \sqrt{50}\) = diameter of the inscribed circle.
The radius of the inscribed circle = \(\frac{\sqrt{50}}{2}\)
\(\text{Area of the circle} = \pi \times r^2 = \pi \times (\frac{\sqrt{50}}{2})^2 = \pi \frac{50}{4} = \frac{25 \pi}{2}\)
The answer is Choice B
