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Point O is the center of the semicircle. If ∠ BCO = 30 ° and
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Updated on: 03 Dec 2018, 11:13
Updated on: 03 Dec 2018, 11:13
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Point O is the center of the semicircle. If ∠ BCO = 30 ° and \(BC = 6 \sqrt{3}\) what is the area of triangle ABO?
GRE exam - Point O is the center of the semicircle..jpg [ 9.5 KiB | Viewed 8029 times ]
A. \(4 \sqrt{3}\)
B. \(6 \sqrt{3}\)
C. \(9 \sqrt{3}\)
D. \(12 \sqrt{3}\)
E. \(24 \sqrt{3}\)
Attachment:
GRE exam - Point O is the center of the semicircle..jpg [ 9.5 KiB | Viewed 8029 times ]
A. \(4 \sqrt{3}\)
B. \(6 \sqrt{3}\)
C. \(9 \sqrt{3}\)
D. \(12 \sqrt{3}\)
E. \(24 \sqrt{3}\)
Re: Point O is the center of the semicircle. If ∠ BCO = 30 ° and
[#permalink]
03 Dec 2018, 10:54
03 Dec 2018, 10:54
2
Missing information from the prompt.
Should state: BC = 6√3
Should state: BC = 6√3
Re: Point O is the center of the semicircle. If ∠ BCO = 30 ° and
[#permalink]
03 Dec 2018, 11:14
03 Dec 2018, 11:14
Expert Reply
Thank you so much. Did not show up.
Regards
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