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If x – y = p, then 2x^2 − 4xy + 2y^2 =
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19 Feb 2021, 09:27
19 Feb 2021, 09:27
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If \(x – y = p\), then \(2x^2 − 4xy + 2y^2 =\)
(A) p
(B) 2p
(C) 4p
(D) \(p^2 \)
(E) \(2p^2\)
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
(A) p
(B) 2p
(C) 4p
(D) \(p^2 \)
(E) \(2p^2\)
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Re: If x – y = p, then 2x^2 − 4xy + 2y^2 =
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19 Feb 2021, 10:11
19 Feb 2021, 10:11
Hi,
We can start by squaring x-y=p
Thus we get x^2-2xy+y^2=p^2
Now, we can multiply the whole equation by 2
2x^2-4xy+y^2=2p^2
IMO E
Hope this helps!
We can start by squaring x-y=p
Thus we get x^2-2xy+y^2=p^2
Now, we can multiply the whole equation by 2
2x^2-4xy+y^2=2p^2
IMO E
Hope this helps!
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Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: If x – y = p, then 2x^2 − 4xy + 2y^2 =
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19 Feb 2021, 10:17
19 Feb 2021, 10:17
1
Carcass wrote:
If \(x – y = p\), then \(2x^2 − 4xy + 2y^2 =\)
(A) p
(B) 2p
(C) 4p
(D) \(p^2 \)
(E) \(2p^2\)
(A) p
(B) 2p
(C) 4p
(D) \(p^2 \)
(E) \(2p^2\)
Given: x – y = p
2x² − 4xy + 2y² = 2(x² − 2xy + y²)
= 2(x - y)²
= 2(p)²
Answer: E
Cheers,
Brent
