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If 8^n+1 + 8^n = 36
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11 Dec 2018, 13:48
11 Dec 2018, 13:48
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Question Stats:
82% (01:13) correct
17% (01:48) wrong based on 40 sessions
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If \(8^{n+1} + 8^n = 36\), then n=
A. \(\frac{1}{3}\)
B. \(\frac{1}{2}\)
C. \(\frac{3}{5}\)
D. \(\frac{2}{3}\)
E. \(\frac{4}{5}\)
A. \(\frac{1}{3}\)
B. \(\frac{1}{2}\)
C. \(\frac{3}{5}\)
D. \(\frac{2}{3}\)
E. \(\frac{4}{5}\)
Re: If 8^n+1 + 8^n = 36
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15 Dec 2018, 07:15
15 Dec 2018, 07:15
2
\(8^n^+^1 + 8^n = 36\)
or, \(8^n(8+1) = 36\)
or, \(8^n * 9 = 36\)
or, \(8^n = 4\)
or, \((2^3)^n = 2^2\)
or, \(2^3^n = 2^2\)
or, \(n = \frac{2}{3}\)
or, \(8^n(8+1) = 36\)
or, \(8^n * 9 = 36\)
or, \(8^n = 4\)
or, \((2^3)^n = 2^2\)
or, \(2^3^n = 2^2\)
or, \(n = \frac{2}{3}\)
gmatclubot
Re: If 8^n+1 + 8^n = 36 [#permalink]
15 Dec 2018, 07:15
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