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In the figure, ABCD is a square and BCP is an equilateral t
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24 Mar 2019, 00:08
24 Mar 2019, 00:08
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Expert Reply
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Question Stats:
92% (05:12) correct
7% (01:17) wrong based on 14 sessions
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#GREpracticequestion In the figure, ABCD is a square.jpg [ 31.21 KiB | Viewed 5519 times ]
In the figure, ABCD is a square and BCP is an equilateral triangle. What is the measure of x ?
(A) 7.5
(B) 15
(C) 30
(D) 45
(E) 60
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Re: In the figure, ABCD is a square and BCP is an equilateral t
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04 Apr 2019, 17:33
04 Apr 2019, 17:33
1
Expert Reply
Carcass wrote:
Attachment:
#GREpracticequestion In the figure, ABCD is a square.jpg
In the figure, ABCD is a square and BCP is an equilateral triangle. What is the measure of x ?
(A) 7.5
(B) 15
(C) 30
(D) 45
(E) 60
Since PC = DC, we see that triangle PCD is an isosceles triangle. We see that angle PCD = 60 + 90 = 150 degrees. Using triangle PCD, we have:
2y + 150 = 180
2y = 30
y = 15
So angle DPC = 15 degrees, and we can see that angle BPA = 15 degrees. Since angle BPC = 60 degrees, then angle APD, or x, is 60 - 2(15) = 30 degrees.
Answer: C
gmatclubot
Re: In the figure, ABCD is a square and BCP is an equilateral t [#permalink]
04 Apr 2019, 17:33
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