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In quadrilateral ABCD, A measures 20 degrees more than the
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11 Apr 2019, 16:08
11 Apr 2019, 16:08
Expert Reply
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Question Stats:
89% (01:53) correct
10% (01:12) wrong based on 28 sessions
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In quadrilateral \(ABCD\), \(\angle A\) measures 20 degrees more than the average of the other three angles of the quadrilateral. Then \(\angle A\)=
(A) 70°
(B) 85°
(C) 95°
(D) 105°
(E) 110°
(A) 70°
(B) 85°
(C) 95°
(D) 105°
(E) 110°
Re: In quadrilateral ABCD, A measures 20 degrees more than the
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13 Oct 2019, 06:53
13 Oct 2019, 06:53
3
The internal angles sum in a quadrilateral is 360 degrees.
If we call av the average of three of the angles, then av*3 + a = 360.
Since a = av + 20, then av*3 + av = av*4 = 360.
Then av = 85 degree and a = 105 degrees.
Answer is D.
If we call av the average of three of the angles, then av*3 + a = 360.
Since a = av + 20, then av*3 + av = av*4 = 360.
Then av = 85 degree and a = 105 degrees.
Answer is D.
Re: In quadrilateral ABCD, A measures 20 degrees more than the
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20 Oct 2019, 11:19
20 Oct 2019, 11:19
Ugh im so bad at these problems. Thanks for the solution
