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The sum of the first n terms of an arithmetic series whose n
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02 May 2019, 02:30
02 May 2019, 02:30
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Question Stats:
74% (01:42) correct
24% (01:35) wrong based on 28 sessions
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The sum of the first \(n\) terms of an arithmetic series whose \(n\)th term is \(n\) can be calculated by the formula \(\frac{n(n + 1)}{2}\).
Which one of the following equals the sum of the first eight terms in a series whose \(n\)th term is \(2n\) ?
(A) 24
(B) 48
(C) 56
(D) 72
(E) 96
Which one of the following equals the sum of the first eight terms in a series whose \(n\)th term is \(2n\) ?
(A) 24
(B) 48
(C) 56
(D) 72
(E) 96
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Re: The sum of the first n terms of an arithmetic series whose n
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09 Apr 2020, 22:17
09 Apr 2020, 22:17
Anybody want to answer this?
I think the answer is D, however, i am not confident.
8(8+1)/2 * 2 =72
I think the answer is D, however, i am not confident.
8(8+1)/2 * 2 =72
Re: The sum of the first n terms of an arithmetic series whose n
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10 Apr 2020, 05:04
10 Apr 2020, 05:04
1
Sn = 1+2+3+4+5+6+7+8=36
S2n =2(1+2+3+4+5+6+7+8)=2*36=72
hence ans is D
S2n =2(1+2+3+4+5+6+7+8)=2*36=72
hence ans is D
