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Eric and Ortega and their teammates watch a movie. They all
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16 May 2019, 00:16
16 May 2019, 00:16
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Question Stats:
60% (01:21) correct
39% (01:45) wrong based on 38 sessions
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Eric and Ortega and their teammates watch a movie. They all sit in a row, and they can sit in n different ways. In how many of the ways can Eric sit to the right of Ortega?
(A) \(n\)
(B) \(\frac{n}{2}\)
(C) \(\frac{n}{3}\)
(D) \(\frac{n}{4}\)
(E) \(\frac{n}{5}\)
(A) \(n\)
(B) \(\frac{n}{2}\)
(C) \(\frac{n}{3}\)
(D) \(\frac{n}{4}\)
(E) \(\frac{n}{5}\)
Re: Eric and Ortega and their teammates watch a movie. They all
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22 Aug 2019, 18:08
22 Aug 2019, 18:08
Carcass wrote:
Eric and Ortega and their teammates watch a movie. They all sit in a row, and they can sit in n different ways. In how many of the ways can Eric sit to the right of Ortega?
(A) \(n\)
(B) \(\frac{n}{2}\)
(C) \(\frac{n}{3}\)
(D) \(\frac{n}{4}\)
(E) \(\frac{n}{5}\)
(A) \(n\)
(B) \(\frac{n}{2}\)
(C) \(\frac{n}{3}\)
(D) \(\frac{n}{4}\)
(E) \(\frac{n}{5}\)
An explanation would be lovely
Re: Eric and Ortega and their teammates watch a movie. They all
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23 Aug 2019, 00:26
23 Aug 2019, 00:26
1
Expert Reply
It is equally likely that Eric sits to the right of Ortega, or not. Hence, in exactly half of the n possible arrangements, Eric sits to the right of Ortega.
B is the answer
B is the answer
