GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
The last digit of the positive even number n equals the last
[#permalink]
20 Apr 2018, 11:25
20 Apr 2018, 11:25
1
Expert Reply
1
Bookmarks
00:00
Question Stats:
42% (00:33) correct
57% (00:41) wrong based on 52 sessions
Hide Show timer Statistics
The last digit of the positive even number n equals the last digit of \(n^2\) . Which one of the following could be n ?
(A) 12
(B) 14
(C) 15
(D) 16
(E) 17
(A) 12
(B) 14
(C) 15
(D) 16
(E) 17
Re: The last digit of the positive even number n equals the last
[#permalink]
08 May 2018, 04:04
08 May 2018, 04:04
what kind of question is this..completely went bouncer.
Re: The last digit of the positive even number n equals the last
[#permalink]
08 May 2018, 11:47
08 May 2018, 11:47
1
Expert Reply
You should stay calm and apply techniques useful for your goal.
If you use the answer choices to reach the solution the question is easy.
The stem says an even positive number so C and E are suddenly out.
Now n must match the last digit of \(n^2\)
12 = 144 ---- 2 and four. does not fit
14 = 196 ----- 4 and 6. does not match
16 = 4.096 ----- 6 and 6. Match. D is the answer.
You could recognize that \(6^2\) is always a number that ends in 6.
Hope this helps
Regards
If you use the answer choices to reach the solution the question is easy.
The stem says an even positive number so C and E are suddenly out.
Now n must match the last digit of \(n^2\)
12 = 144 ---- 2 and four. does not fit
14 = 196 ----- 4 and 6. does not match
16 = 4.096 ----- 6 and 6. Match. D is the answer.
You could recognize that \(6^2\) is always a number that ends in 6.
Hope this helps
Regards
GRE is all about learning from our mistakes and not repeating them, I can understand.
