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What is the value of
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15 Jul 2019, 02:47
15 Jul 2019, 02:47
Expert Reply
00:00
Question Stats:
96% (01:04) correct
3% (00:32) wrong based on 28 sessions
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What is the value of \((3-\frac{1}{3})^2+(3+\frac{1}{3})^2\) ?
A. \(\frac{122}{9}\)
B. \(\frac{164}{9}\)
C. \(36\)
D. \(\frac{164}{3}\)
E. \(162\)
A. \(\frac{122}{9}\)
B. \(\frac{164}{9}\)
C. \(36\)
D. \(\frac{164}{3}\)
E. \(162\)
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: What is the value of
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17 Jul 2019, 05:28
17 Jul 2019, 05:28
Carcass wrote:
What is the value of \((3-\frac{1}{3})^2+(3+\frac{1}{3})^2\) ?
A. \(\frac{122}{9}\)
B. \(\frac{164}{9}\)
C. \(36\)
D. \(\frac{164}{3}\)
E. \(162\)
A. \(\frac{122}{9}\)
B. \(\frac{164}{9}\)
C. \(36\)
D. \(\frac{164}{3}\)
E. \(162\)
\((3-\frac{1}{3})^2+(3+\frac{1}{3})^2=(\frac{9}{3}-\frac{1}{3})^2+(\frac{9}{3}+\frac{1}{3})^2\)
\(=(\frac{8}{3})^2+(\frac{10}{3})^2\)
\(=(\frac{8}{3})(\frac{8}{3})+(\frac{10}{3})(\frac{10}{3})\)
\(=\frac{64}{9}+\frac{100}{9}\)
\(=\frac{164}{9}\)
Answer: B
Cheers,
Brent
gmatclubot
Re: What is the value of [#permalink]
17 Jul 2019, 05:28
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