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Which of the following is equal to
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13 Jul 2019, 01:26
13 Jul 2019, 01:26
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Which of the following is equal to \(\frac{-1}{2x} - \frac{1}{4y} + \frac{1}{xy} + \frac{1}{8}\) ?
A. \(\frac{(x-4)(2-y)}{8xy}\)
B. \(\frac{(x-2)(y-4)}{8xy}\)
C. \(\frac{(x-4)(y-2)}{8xy}\)
D. \(\frac{(x+2)(4-y)}{8xy}\)
E. \(\frac{(x-2)(4-y)}{8xy}\)
A. \(\frac{(x-4)(2-y)}{8xy}\)
B. \(\frac{(x-2)(y-4)}{8xy}\)
C. \(\frac{(x-4)(y-2)}{8xy}\)
D. \(\frac{(x+2)(4-y)}{8xy}\)
E. \(\frac{(x-2)(4-y)}{8xy}\)
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Joined: 09 Apr 2020
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Re: Which of the following is equal to
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18 Apr 2020, 21:20
18 Apr 2020, 21:20
2
Expert Reply
Carcass wrote:
Which of the following is equal to \(\frac{-1}{2x} - \frac{1}{4y} + \frac{1}{xy} + \frac{1}{8}\) ?
A. \(\frac{(x-4)(2-y)}{8xy}\)
B. \(\frac{(x-2)(y-4)}{8xy}\)
C. \(\frac{(x-4)(y-2)}{8xy}\)
D. \(\frac{(x+2)(4-y)}{8xy}\)
E. \(\frac{(x-2)(4-y)}{8xy}\)
A. \(\frac{(x-4)(2-y)}{8xy}\)
B. \(\frac{(x-2)(y-4)}{8xy}\)
C. \(\frac{(x-4)(y-2)}{8xy}\)
D. \(\frac{(x+2)(4-y)}{8xy}\)
E. \(\frac{(x-2)(4-y)}{8xy}\)
First, find a common denominator: \(8xy\)
Rewrite each expression using 8xy as the denominator: \(\frac{-4y}{8xy}-\frac{2x}{8xy}+\frac{8}{8xy}+\frac{xy}{8xy}\)
Add up the numerators: \(-4y-2x+8+xy\) (since the denominator is the same in all answer choices, we can disregard it)
Group the x terms together and the y terms together: \(xy-4y-2x+8\)
Factor each group: \(y(x-4)-2(x-4)\)
And distribute: \((x-4)(y-2)\)
Only one answer choice matches that numerator.
Answer: C
Which of the following is equal to
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08 Mar 2024, 20:57
08 Mar 2024, 20:57
1
\(\dfrac{-1}{2x} - \dfrac{1}{4y} + \dfrac{1}{xy} + \dfrac{1}{8}\)
Solve this by taking the LCM
LCM of \(2x\), \(4y\), \(xy\) and \(8\) is \(8xy\)
We now add them all
\(\dfrac{-4y - 2x + 8 + xy}{8xy}\)
\(\dfrac{x(-2+y)-4(y-2)}{8xy}\)
\(\dfrac{(x-4)(y-2)}{8xy}\)
The answer is C
Solve this by taking the LCM
LCM of \(2x\), \(4y\), \(xy\) and \(8\) is \(8xy\)
We now add them all
\(\dfrac{-4y - 2x + 8 + xy}{8xy}\)
\(\dfrac{x(-2+y)-4(y-2)}{8xy}\)
\(\dfrac{(x-4)(y-2)}{8xy}\)
The answer is C
