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The volume of a cube is 1 cubic ft . The distance from any vertex to t
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18 Jan 2025, 00:36
18 Jan 2025, 00:36
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The volume of a cube is 1 cubic ft . The distance from any vertex to the centre of the cube (in feet) is
(A) $12$
(B) $\frac{1}{\sqrt{2$
(C) $√2$
(D) $√32$
(E) $√3$
(A) $12$
(B) $\frac{1}{\sqrt{2$
(C) $√2$
(D) $√32$
(E) $√3$
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The volume of a cube is 1 cubic ft . The distance from any vertex to t
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23 Feb 2025, 02:17
23 Feb 2025, 02:17
Expert Reply
The volume of a cube is Side $3=1$ cubic feet $\Rightarrow$ Side $=3√1=1$ feet
Now, the distance from any vertex to the centre of the cube is same as $12$ the length of the diagonal i.e. $12$ of $√3=√32$
$(∵$ Diagonal in a cube is $\sqrt{3} \times$ Side $)$
Hence the answer is (D).
Now, the distance from any vertex to the centre of the cube is same as $12$ the length of the diagonal i.e. $12$ of $√3=√32$
$(∵$ Diagonal in a cube is $\sqrt{3} \times$ Side $)$
Hence the answer is (D).
gmatclubot
The volume of a cube is 1 cubic ft . The distance from any vertex to t [#permalink]
23 Feb 2025, 02:17
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