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(2x+1)^2 - (2x-1) ^2 =
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05 Dec 2017, 13:16
05 Dec 2017, 13:16
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Question Stats:
79% (00:49) correct
20% (00:53) wrong based on 39 sessions
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Re: (2x+1)^2 - (2x-1) ^2 =
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06 Dec 2017, 08:00
06 Dec 2017, 08:00
Carcass wrote:
here,
it can be written as
\((4x^2 + 4x + 1) - (4x^2 - 4x + 1) = 8x\)
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Re: (2x+1)^2 - (2x-1) ^2 =
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31 Dec 2021, 02:36
31 Dec 2021, 02:36
Given that \((2x+1) ^2 - (2x-1) ^2 =\)
This is of the form \((a+b)^2 - (a-b)^2 = 4ab\)
=> [m](2x+1) ^2 - (2x-1) ^2 = 4 * 2x*1 = 8x
So, Answer will be B
Hope it helps!
This is of the form \((a+b)^2 - (a-b)^2 = 4ab\)
=> [m](2x+1) ^2 - (2x-1) ^2 = 4 * 2x*1 = 8x
So, Answer will be B
Hope it helps!
