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If sqrt x+3= sqrt x+ sqrt 3
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24 Feb 2020, 05:02
24 Feb 2020, 05:02
Expert Reply
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Question Stats:
10% (00:21) correct
89% (00:40) wrong based on 28 sessions
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If \(\sqrt{x+3}=\sqrt{ x}+ \sqrt{3}\) then x is
A. 0
B. 2
C. \(\sqrt{3 }\)
D. 3
E. any non-negative real number
Kudos for the right answer and explanation[/m]
A. 0
B. 2
C. \(\sqrt{3 }\)
D. 3
E. any non-negative real number
Kudos for the right answer and explanation[/m]
Re: If sqrt x+3= sqrt x+ sqrt 3
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24 Feb 2020, 09:37
24 Feb 2020, 09:37
2
Carcass wrote:
If \(\sqrt{x+3}=\sqrt{ x}+ \sqrt{3}\) then x is
A. 0
B. 2
C. \(\sqrt{3 }\)
D. 3
E. any non-negative real number
Kudos for the right answer and explanation[/m]
A. 0
B. 2
C. \(\sqrt{3 }\)
D. 3
E. any non-negative real number
Kudos for the right answer and explanation[/m]
Here,
\(\sqrt{x+3}=\sqrt{ x}+ \sqrt{3}\)
Squaring both sides
\(x + 3 = x + 3 + 2\sqrt{3x}\)
or \(2\sqrt{3x} = 0\)
or \(\sqrt{3x} = 0\)
Squaring both sides
\(3x = 0\)
or \(x = 0\)
Re: If sqrt x+3= sqrt x+ sqrt 3
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24 Feb 2020, 11:21
24 Feb 2020, 11:21
Expert Reply
I think this question is falter.
The answer is B and even if you substitute 2 in the roots the equivalence does not hold true.
The answer is B and even if you substitute 2 in the roots the equivalence does not hold true.
