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If a, b, and c are three different numbers and ax : by : cz
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13 Apr 2019, 06:29
13 Apr 2019, 06:29
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If a, b, and c are three different numbers and ax : by : cz = 1 : 2 : –3, then ax + by + cz =
(A) 0
(B) \(\frac{1}{2}\)
(C) 3
(D) 6
(E) 9
(A) 0
(B) \(\frac{1}{2}\)
(C) 3
(D) 6
(E) 9
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Re: If a, b, and c are three different numbers and ax : by : cz
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07 Jun 2020, 03:54
07 Jun 2020, 03:54
ax : by : cz = 1 : 2 : –3
Since they are in the ratio 1 : 2: -3 so they can be taken as 1*k : 2*k : -3*k where k was some common number which got cancelled when we took the ratio
So, ax + by + cz = k + 2k - 3k = 0
So, answer will be A
Hope it helps!
Since they are in the ratio 1 : 2: -3 so they can be taken as 1*k : 2*k : -3*k where k was some common number which got cancelled when we took the ratio
So, ax + by + cz = k + 2k - 3k = 0
So, answer will be A
Hope it helps!
gmatclubot
Re: If a, b, and c are three different numbers and ax : by : cz [#permalink]
07 Jun 2020, 03:54
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