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If f^2 g < 0, which of the following must be true?
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09 Aug 2018, 03:51
09 Aug 2018, 03:51
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Question Stats:
93% (00:18) correct
6% (01:51) wrong based on 87 sessions
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If\(f^2 g < 0\), which of the following must be true?
(A)\(f < 0\)
(B) \(g < 0\)
(C) \(fg < 0\)
(D) \(fg > 0\)
(E) \(f^2 < 0\)
(A)\(f < 0\)
(B) \(g < 0\)
(C) \(fg < 0\)
(D) \(fg > 0\)
(E) \(f^2 < 0\)
Re: If f^2 g < 0, which of the following must be true?
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09 Aug 2018, 14:01
09 Aug 2018, 14:01
1
Carcass wrote:
If\(f^2 g < 0\), which of the following must be true?
(A)\(f < 0\)
(B) \(g < 0\)
(C) \(fg < 0\)
(D) \(fg > 0\)
(E) \(f^2 < 0\)
(A)\(f < 0\)
(B) \(g < 0\)
(C) \(fg < 0\)
(D) \(fg > 0\)
(E) \(f^2 < 0\)
Given
If\(f^2 g < 0\)
As f^2 is always positive g has to be negative.
The best answer is B.
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Re: If f^2 g < 0, which of the following must be true?
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28 Dec 2021, 01:20
28 Dec 2021, 01:20
1
Given that \(f^2 g < 0\)
We know that Square of a number is always >= 0
=> \(f^2\) >= 0
So, for \(f^2 g < 0\), g has to be < 0
As product of two numbers is negative only one one is positive and other is negative.
=> g < 0
So, Answer will be B
Hope it helps!
Watch the following video to learn the Basics of Inequalities
We know that Square of a number is always >= 0
=> \(f^2\) >= 0
So, for \(f^2 g < 0\), g has to be < 0
As product of two numbers is negative only one one is positive and other is negative.
=> g < 0
So, Answer will be B
Hope it helps!
Watch the following video to learn the Basics of Inequalities
