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The figure above shows some of the dimensions
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03 Jun 2020, 05:35
03 Jun 2020, 05:35
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59% (02:19) correct
40% (02:48) wrong based on 61 sessions
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The figure above shows some of the dimensions of a triangular plaza with an L-shaped walk along two of its edges. If the width of the walk is 4 feet and the total area of the plaza and walk together is 10,800 square feet, what is the value of x ?
A. 200
B. 204
C. 212
D. 216
E. 225
Re: The figure above shows some of the dimensions
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03 Jun 2020, 05:35
03 Jun 2020, 05:35
Expert Reply
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Re: The figure above shows some of the dimensions
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03 Jun 2020, 05:47
03 Jun 2020, 05:47
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Carcass wrote:
The figure above shows some of the dimensions of a triangular plaza with an L-shaped walk along two of its edges. If the width of the walk is 4 feet and the total area of the plaza and walk together is 10,800 square feet, what is the value of x ?
A. 200
B. 204
C. 212
D. 216
E. 225
Let's add a line to divide the figure into 3 separate shapes
(area of blue triangle) + (area of red rectangle) + (area of green rectangle) = 10,800
Area of triangle = (base)(height)/2
So, we get: (x)(96)/2 + 4x + (4)(100) = 10,800
Simplify: 48x + 4x + 400 = 10,800
Simplify: 52x + 400 = 10,800
Subtract 400 from both sides to get: 52x = 10,400
Solve: x = 10,400/52 = 200
Answer: A
Cheers,
Brent
