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Certain amount of solution with 20% concentration of salt ...

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motion2020
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Certain amount of solution with 20% concentration of salt ... [#permalink] New post   29 Jul 2021, 16:01
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Certain amount of a solution with 20% concentration of salt is heated to loose half of its volume. The remaining solution is added by 4 liters of the solution with 30% concentration of salt. Find the amount of evaporated solution in liters, if the final solution has 24% concentration of salt and heating does not change the concentration of salt in a solution.

(A) 9
(B) 8
(C) 7
(D) 6
(E) 5
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D
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KarunMendiratta
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Certain amount of solution with 20% concentration of salt ... [#permalink] New post   29 Jul 2021, 21:00
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motion2020 wrote:
Certain amount of a solution with 20% concentration of salt is heated to loose half of its volume. The remaining solution is added by 4 liters of the solution with 30% concentration of salt. Find the amount of evaporated solution in liters, if the final solution has 24% concentration of salt and heating does not change the concentration of salt in a solution.

(A) 9
(B) 8
(C) 7
(D) 6
(E) 5


Let the initial solution be of \(x\) liters

20% of \(\frac{x}{2}\) + 30% of 4 liters = 24% of (\(\frac{x}{2}\) + 4)
10x + 120 = 12x + 96
2x = 24
x = 12

Amount of evaporated solution is half of \(x\) i.e. 6 liters
Hence, option D
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aishumurali
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Re: Certain amount of solution with 20% concentration of salt ... [#permalink] New post   18 Aug 2021, 18:29
Are there more sums like this to practise?
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KarunMendiratta
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Re: Certain amount of solution with 20% concentration of salt ... [#permalink] New post   18 Aug 2021, 21:54
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aishumurali wrote:
Are there more sums like this to practise?


https://gre.myprepclub.com/forum/3-liters-of-solution-with-45-concentration-23689.html#p75350
https://gre.myprepclub.com/forum/solution-x-is-10-percent-alcohol-by-volume-and-solution-y-i-55.html#p63849
https://gre.myprepclub.com/forum/a-cleaning-solution-mixture-20366.html#p60229
https://gre.myprepclub.com/forum/solution-y-is-40-percent-sugar-by-volume-and-solution-x-is-20-percent-22734.html#p69883
https://gre.myprepclub.com/forum/marcia-has-2-liters-l-of-a-60-concentrated-solution-of-ph-11653.html#p74693
https://gre.myprepclub.com/forum/if-there-are-10-liters-of-a-20-solution-of-alcohol-how-much-water-sh-22743.html#p76952
https://gre.myprepclub.com/forum/topic9375.html#p74291
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Carcass
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Re: Certain amount of solution with 20% concentration of salt ... [#permalink] New post   19 Aug 2021, 04:44
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aishumurali wrote:
Are there more sums like this to practise?


Just click above in the first post the tag mixture problems aND YOU WILL HAVE THE FOLLOWING

https://gre.myprepclub.com/forum/search.ph ... tag_id=359

The tags are a very powerful resource to exploit

Regards
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LamoBear02
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Re: Certain amount of solution with 20% concentration of salt ... [#permalink] New post   01 Aug 2023, 00:06
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I approached this problem in a weird but I got the answer so idk if it's the most reliable way;
1) I Knew that S1 has 20% of salt and S2 has 30% of salt. when added with each other the new soln has 24% salt so:
20----24------30. as we can see that 24 is closer to 20 so the new soln contains more of S1 and ratio of S1 and S2 in the new soln, let's say Y is S1:S2 = 6:4.
2) We know that 4 litre of S2 was added. so by going with the current Ratio we'd have 4 litres of S2 and 6 litres of S1.
3) Problem solved? Not so fast. We know that before adding S2, S1 was heated to lose half of its volume. So, the initial would have been twice the volume of S1 currently which is 6. so S1 (initially) would have been 12. so, 6 ounces of it were heated.
Carcass, Greenlight Test Prep could you evaluate and verify (if true) my approach?
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Tariq16s
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Re: Certain amount of solution with 20% concentration of salt ... [#permalink] New post   26 Jun 2024, 17:00
didn't the salt conc. Increase After evaporation?

Posted from my mobile device
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Mridu2024
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Re: Certain amount of solution with 20% concentration of salt ... [#permalink] New post   28 Jun 2024, 03:46
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Find the salt content in the original solution with 20 percent salt concentration. Let us consider total volume of solution is x liters, so after heating the amount remain shall be x/2 liters. This x/2 liters is what is to be found out.
Now , salt content of it shall be 20 percent of x/ 2 = x/10
The new solution added is 30 percent salt by concentration and volume is 4 liters, so salt in it is 30/100 of 4 liters = 1.2 liters.

Now according to the problem

x/10 + 1.2 = ( x/2 + 4) * 24/100

solving X = 6
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Re: Certain amount of solution with 20% concentration of salt ... [#permalink]
28 Jun 2024, 03:46
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