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If x is divisible by both 3 and 4, then the number x must be
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20 Apr 2018, 11:24
20 Apr 2018, 11:24
Expert Reply
00:00
Question Stats:
92% (00:28) correct
7% (01:05) wrong based on 39 sessions
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If x is divisible by both 3 and 4, then the number x must be a multiple of which one of the following?
(A) 8
(B) 12
(C) 15
(D) 18
(E) 21
(A) 8
(B) 12
(C) 15
(D) 18
(E) 21
Re: If x is divisible by both 3 and 4, then the number x must be
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Updated on: 09 May 2018, 05:14
Updated on: 09 May 2018, 05:14
1
I got the answer right but I belive the way I made my pattern for the solution of this question is was pedestrian- if anyone could solve it in a more slick manner then it is most welcome.
For me I made two equation
X=3k+0---eq 1
X=4K+0
now multile of 3 as per eq 1 are as follows
3,6,9,12,15,18,21,24,27,30--- as we can see 12 and 24 can be dividend completely by 12 which is 3*4 hence I chose the answer B..
this took TIME ..any shortcut pls welcome
For me I made two equation
X=3k+0---eq 1
X=4K+0
now multile of 3 as per eq 1 are as follows
3,6,9,12,15,18,21,24,27,30--- as we can see 12 and 24 can be dividend completely by 12 which is 3*4 hence I chose the answer B..
this took TIME ..any shortcut pls welcome
Re: If x is divisible by both 3 and 4, then the number x must be
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08 May 2018, 12:22
08 May 2018, 12:22
1
Expert Reply
3*4=12
12-24-48......and so forth
B is the answer.
OR
The only number that has 3 and 4 as factors among the answer choices is 12. The others do not.
OR
because the factors are 3 and 4 the number must be even. So, C and E are out. 8 is 2^3 and 18 is 3^2 * 2. In 8 is missing the 3 and in the latter is missing the 4.
Hope is clear now.
Regards
12-24-48......and so forth
B is the answer.
OR
The only number that has 3 and 4 as factors among the answer choices is 12. The others do not.
OR
because the factors are 3 and 4 the number must be even. So, C and E are out. 8 is 2^3 and 18 is 3^2 * 2. In 8 is missing the 3 and in the latter is missing the 4.
Hope is clear now.
Regards
.. X has to be a multiple of 12.
