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In the figure above, the areas of square regions X and Y are
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11 Dec 2020, 22:21
11 Dec 2020, 22:21
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64% (00:52) correct
35% (00:25) wrong based on 14 sessions
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GRE In the figure above, the areas of square regions X.jpg [ 8.56 KiB | Viewed 1448 times ]
In the figure above, the areas of square regions X and Y are 1 and 4, respectively. What is the area of the triangular region?
A. 2
B. 1
C. 3/4
D. 1/2
E. 1/4
Re: In the figure above, the areas of square regions X and Y are
[#permalink]
12 Dec 2020, 03:13
12 Dec 2020, 03:13
1
as the length of sides are 2 and 1 unit of bigger and smaller respectively.
the point where the bigger side and the smaller side of two squares meet forms a 90-degree angle, which implies the triangle that is formed by the sides of squares and another side is a right-angle triangle. therefore, 2 and 1 are the length of height and base of the right triangle.
thus the area of the tringle is 1/2*1*2=1 (B is the answer)
the point where the bigger side and the smaller side of two squares meet forms a 90-degree angle, which implies the triangle that is formed by the sides of squares and another side is a right-angle triangle. therefore, 2 and 1 are the length of height and base of the right triangle.
thus the area of the tringle is 1/2*1*2=1 (B is the answer)
gmatclubot
Re: In the figure above, the areas of square regions X and Y are [#permalink]
12 Dec 2020, 03:13
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