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There are 100 apples in a bag of which 98% are green and the rest red.
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14 Jan 2021, 03:30
14 Jan 2021, 03:30
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Question Stats:
67% (01:44) correct
32% (01:38) wrong based on 90 sessions
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There are 100 apples in a bag of which 98% are green and the rest red. How many green apples do you need to remove so that only 96% of the apples are green?
A. 40
B. 8
C. 15
D. 25
E. 50
A. 40
B. 8
C. 15
D. 25
E. 50
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Re: There are 100 apples in a bag of which 98% are green and the rest red.
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14 Jan 2021, 06:34
14 Jan 2021, 06:34
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Carcass wrote:
There are 100 apples in a bag of which 98% are green and the rest red. How many green apples do you need to remove so that only 96% of the apples are green?
A. 40
B. 8
C. 15
D. 25
E. 50
A. 40
B. 8
C. 15
D. 25
E. 50
There are 100 apples in a bag of which 98% are green and the rest red.
So, we can conclude that (initially) there are 98 green apples and 2 red apples in the bag.
If (after we remove some green apples) 96% of the apples are green. This means that 4% of the apples are red.
So, let's reword the question as "How many green apples do you need to remove so that 4% of the apples are red?"
We already know there are 2 red apples, and we know that 2/50 = 4%
That is, if there were 50 apples altogether, and 2 were red, then 4% of the apples would be red.
In order to get 50 apples altogether, we must remove 50 apples from the bag.
Answer: E
Re: There are 100 apples in a bag of which 98% are green and the rest red.
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18 Oct 2021, 03:38
18 Oct 2021, 03:38
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By the given information, we can infer that there are 98 green apples and 2 red apples.
Let the amount of green apples to be removed be x.
Now we can set up a equation like-
(98 - x) / (100 - x) = 96/100
Solving this, we get x = 50.
Hence, E
Let the amount of green apples to be removed be x.
Now we can set up a equation like-
(98 - x) / (100 - x) = 96/100
Solving this, we get x = 50.
Hence, E
