Carcass wrote:
The ratio of two positive numbers is 3 to 4. If k is added to each number the new ratio will be 4 to 5, and the sum of the numbers will be 117. What is the value of k ?
A. 1
B. 13
C. 14
D. 18
E. 21
The ratio of two positive numbers is 3 to 4. Let
3x = the smaller number
Let
4x = the larger number
Aside: Notice that this ensures that their ratio will equal 3/4, since
3x/
4x = 3/4
If k is added to each number the new ratio will be 4 to 5 . . . When k is added to each value, the NEW values are
3x + k and
4x + k
So, (
3x + k)/(
4x + k) = 4/5
Cross multiply to get: 16x + 4k = 15x + 5k
Rearrange terms to get:
x = k . . . and the sum of the numbers will be 117 The two NEW values are 3x + k and 4x + k
So, we can write: (3x + k) + (4x + k) = 117
Simplify to get 7x + 2k = 117
Since
x = k , we can take the above equation and replace x with k to get...
7k + 2k = 117
Simplify: 9k = 117
Solve: k = 13
Answer: B
Cheers,
Brent