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(5^(1/2) + 7^(1/2))^2 =
[#permalink]
08 Feb 2021, 07:11
08 Feb 2021, 07:11
Expert Reply
00:00
Question Stats:
78% (00:38) correct
21% (01:09) wrong based on 23 sessions
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\((\sqrt{5}+\sqrt{7})^2=\)
A. 12
B. \(12 + 2\sqrt{3}\)
C. \(12 + 4\sqrt{3}\)
D. \(12 + \sqrt{35}\)
E. \(12 + 2\sqrt{35}\)
Kudos for the right answer and explanation
A. 12
B. \(12 + 2\sqrt{3}\)
C. \(12 + 4\sqrt{3}\)
D. \(12 + \sqrt{35}\)
E. \(12 + 2\sqrt{35}\)
Kudos for the right answer and explanation
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
(5^(1/2) + 7^(1/2))^2 =
[#permalink]
08 Feb 2021, 07:48
08 Feb 2021, 07:48
1
Carcass wrote:
\((\sqrt{5}+\sqrt{7})^2=\)
A. 12
B. \(12 + 2\sqrt{3}\)
C. \(12 + 4\sqrt{3}\)
D. \(12 + \sqrt{35}\)
E. \(12 + 2\sqrt{35}\)
Kudos for the right answer and explanation
A. 12
B. \(12 + 2\sqrt{3}\)
C. \(12 + 4\sqrt{3}\)
D. \(12 + \sqrt{35}\)
E. \(12 + 2\sqrt{35}\)
Kudos for the right answer and explanation
Use the FOIL method....
\((\sqrt{5}+\sqrt{7})=(\sqrt{5}+\sqrt{7})(\sqrt{5}+\sqrt{7})\)
\(= 5 + \sqrt{35} + \sqrt{35} + 7\)
\(= 12 + 2\sqrt{35}\)
Answer: E
gmatclubot
(5^(1/2) + 7^(1/2))^2 = [#permalink]
08 Feb 2021, 07:48
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