We know $\(\mathrm{A}=\mathrm{N}-100 \mathrm{X}-\mathrm{Y}\)$, where ' N ' is a three digit number with ' X ' as its hundreds digit \& ' $\(Y\)$ ' as its units digit.

We have $\(N=X Z Y\)$, where we have taken Z as the tens digit of N

We get $\(A=N-100 X-Y=X Z Y-100 X-Y=100 X+10 Z+Y-100 X-Y=10 Z\)$ which is a multiple of 10 .


A must be divisible by 5

C is the answer