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If all the coins are fair, in that the probability of heads = probab
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16 Jun 2021, 02:16
16 Jun 2021, 02:16
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Maya flipped 24 coins, each of which landed with either a head face-up or a tail face up, hereafter referred to as an outcome of “heads” or “tails.”
If all the coins are fair, in that the probability of “heads” = probability of “tails” = \(\frac{1}{2}\) for every toss, which of the following events has the greatest probability?
A. Of the 24 tosses, the number of “heads” equals 11.
B. Of the 24 tosses, the number of “heads” equals 12.
C. Of the 24 tosses, the number of “tails” equals 14.
D. Of the 24 tosses, the number of “tails” is at most 3.
E. Of the 24 tosses, the number of “heads” is it least 22
If all the coins are fair, in that the probability of “heads” = probability of “tails” = \(\frac{1}{2}\) for every toss, which of the following events has the greatest probability?
A. Of the 24 tosses, the number of “heads” equals 11.
B. Of the 24 tosses, the number of “heads” equals 12.
C. Of the 24 tosses, the number of “tails” equals 14.
D. Of the 24 tosses, the number of “tails” is at most 3.
E. Of the 24 tosses, the number of “heads” is it least 22
Re: If all the coins are fair, in that the probability of heads = probab
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16 Jun 2021, 08:32
16 Jun 2021, 08:32
1
As it is a fair coin with equal chances of heads and tails (50-50), out of X tosses the most probable outcome is X/2 of the tosses are Heads and X/2 of the tosses are Tails.
So of the 24 tosses, 12 heads and 12 tails are the most probable outcome. Answer B.
So of the 24 tosses, 12 heads and 12 tails are the most probable outcome. Answer B.
Re: If all the coins are fair, in that the probability of heads = probab
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21 Jun 2021, 01:34
21 Jun 2021, 01:34
How the probabilities would differ if all the possible outcomes have same probability?
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