motion2020
I am glad we are getting new questions. Kindly add the answer to the question now!

To find the maximum value of x, see how many 5s we can have in 29!
one in 5, 10, 15, and 20
two in 25
So, a total of 6 5s

or we can also find it by using;
\(\frac{29}{5^1}+\frac{29}{5^2}+\frac{29}{5^3}+....\)

Consider only whose fractions with Numerator > Denominator
So, \(\frac{29}{5^1}+\frac{29}{5^2}\)
5 integers + 1 integer value = 6 integer values

Similarly, y would be 17
\(\frac{37}{3^1}+\frac{37}{3^2}+\frac{37}{3^3}\)
12 integers + 4 integers + 1 integer value = 17 integer values

x + y = 23

Hence, option C