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Retired Moderator
Joined: 19 Nov 2020
Posts: 326
Given Kudos: 64
GRE 1: Q160 V152
What is the sum of the roots of equation ...
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Updated on: 31 Jul 2021, 06:49
Updated on: 31 Jul 2021, 06:49
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60% (02:06) wrong based on 5 sessions
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What is the sum of the roots of equation \((x-3)(x-5)={\frac{3}{(x-4)}}-1\) ?
(A) 12
(B) 11
(C) 10
(D) 9
(E) \(4+ 3^{\frac{1}{3}}\)
OA is E.
Previous value edited from 8 to \(4+ 3^{\frac{1}{3}}\)
(A) 12
(B) 11
(C) 10
(D) 9
(E) \(4+ 3^{\frac{1}{3}}\)
OA is E.
Previous value edited from 8 to \(4+ 3^{\frac{1}{3}}\)
Originally posted by motion2020 on 30 Jul 2021, 14:34.
Last edited by motion2020 on 31 Jul 2021, 06:49, edited 2 times in total.
Last edited by motion2020 on 31 Jul 2021, 06:49, edited 2 times in total.
Retired Moderator
Joined: 19 Nov 2020
Posts: 326
Given Kudos: 64
GRE 1: Q160 V152
Re: What is the sum of the roots of equation ...
[#permalink]
31 Jul 2021, 06:43
31 Jul 2021, 06:43
motion2020 wrote:
What is the sum of the roots of equation \((x-3)(x-5)={\frac{3}{(x-4)}}-1\) ?
(A) 12
(B) 11
(C) 10
(D) 9
(E) \(4+3^{\frac{1}{3}}\)
(A) 12
(B) 11
(C) 10
(D) 9
(E) \(4+3^{\frac{1}{3}}\)
\((x-3)(x-5)+1={\frac{3}{(x-4)}}\)
\((x-4) * ((x-3)(x-5) + 1) = 3\), hence x =! 4
\((x-4) * (x^2-5x-3x+15+1) = 3\)
\((x-4)(x-4)^2 = 3\)
\((x-4)^3 = 3\)
\(x = 4+ 3^{\frac{1}{3}}\)
I have edited answer
gmatclubot
Re: What is the sum of the roots of equation ... [#permalink]
31 Jul 2021, 06:43
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