GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Among a population of 24,000 people, 80 percent own a personal compute
[#permalink]
19 Aug 2021, 05:11
19 Aug 2021, 05:11
Expert Reply
1
Bookmarks
00:00
Question Stats:
69% (02:46) correct
30% (03:23) wrong based on 13 sessions
Hide Show timer Statistics
Among a population of 24,000 people, 80 percent own a personal computer, 88 percent own a car, and 72 percent own both a personal computer and a car. If 1 person is to be randomly selected from the 24,000 people, what is the probability that the person selected will be one who owns a car but does NOT own a personal computer?
A. 22/25
B. 1/2
C. 4/25
D. 3/25
E. 2/25
Kudos for the right answer and explanation
Question part of the project GRE Quant/Math Extreme Challenge Daily (2021) Edition
GRE - Math Book
A. 22/25
B. 1/2
C. 4/25
D. 3/25
E. 2/25
Kudos for the right answer and explanation
Question part of the project GRE Quant/Math Extreme Challenge Daily (2021) Edition
GRE - Math Book
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Re: Among a population of 24,000 people, 80 percent own a personal compute
[#permalink]
19 Aug 2021, 08:06
19 Aug 2021, 08:06
Carcass wrote:
Among a population of 24,000 people, 80 percent own a personal computer, 88 percent own a car, and 72 percent own both a personal computer and a car. If 1 person is to be randomly selected from the 24,000 people, what is the probability that the person selected will be one who owns a car but does NOT own a personal computer?
A. 22/25
B. 1/2
C. 4/25
D. 3/25
E. 2/25
A. 22/25
B. 1/2
C. 4/25
D. 3/25
E. 2/25
(Use a venn diagram)
Total = PC + Car - Both PC and Car + None
\(24000 = 19200 + 21120 - 17280\) + None
None = 960
Person who owns a Car but not PC = Car - Both PC and Car = \(21120 - 17280 = 3840\)
Probability = \(\frac{3840}{24000} = 0.16 = \frac{4}{25}\)
Hence, option C
General Discussion
Re: Among a population of 24,000 people, 80 percent own a personal compute
[#permalink]
19 Aug 2021, 08:49
19 Aug 2021, 08:49
1
80% owns a personal computer(p.c.) = 80% of 24000= .8*24000= 19200
88% owns a car = 88% of 24000= .88*24000= 21120
72% owns both= 72% of 24000= .72*24000= 17280
People who owns only pc :
people who owns pc - people who owns both = 19200-17280 = 1920
People who owns only car::
people who owns car - people who owns both = 21120-17280= 3840
If we add this all together (i.e. 1920+3840+17280) we get 23040 which is not equal to the total mentioned in the question, which means 24000-23040 = 960 are the people with no car or pc.
Now we have everything to calculate the probability of owns a car but does NOT own a personal computer
\frac{3840}{24000} = 0.16 OR \frac{4}{25}
Hence the correct answer is option C.
88% owns a car = 88% of 24000= .88*24000= 21120
72% owns both= 72% of 24000= .72*24000= 17280
People who owns only pc :
people who owns pc - people who owns both = 19200-17280 = 1920
People who owns only car::
people who owns car - people who owns both = 21120-17280= 3840
If we add this all together (i.e. 1920+3840+17280) we get 23040 which is not equal to the total mentioned in the question, which means 24000-23040 = 960 are the people with no car or pc.
Now we have everything to calculate the probability of owns a car but does NOT own a personal computer
\frac{3840}{24000} = 0.16 OR \frac{4}{25}
Hence the correct answer is option C.
