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A car leaves New York at 12:00 driving due west at an average speed of
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20 Oct 2021, 09:30
20 Oct 2021, 09:30
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Question Stats:
67% (02:02) correct
32% (02:32) wrong based on 71 sessions
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A car leaves New York at 12:00 driving due west at an average speed of 54 miles per hour. A second car leaves New York 2 hours later, driving due west on the same road, at an average speed of 66 miles per hour. If both cars continue to move at the same rates, at what time will the second car reach the first?
9:00
10:00
10:30
11:00
11:30
9:00
10:00
10:30
11:00
11:30
GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2928
Given Kudos: 1257
GPA: 3.39
Re: A car leaves New York at 12:00 driving due west at an average speed of
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27 Oct 2021, 06:40
27 Oct 2021, 06:40
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Expert Reply
+1 Kudos to posts containing answer with explanation
A car leaves New York at 12:00 driving due west at an average speed of
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31 Oct 2021, 02:14
31 Oct 2021, 02:14
2
I don't know if this is the proper way to approach this problem, but here it goes:
Let t be the start time at which car1 starts. So the distance travelled by car 1 would be d= 54t
Car 2 leaves 2 hours later. The distance travelled by car 1 would be d = 66(t+2).
54t = 66(t+2)
Solving the above should give the time as 11 hours. Adding 11 hours to 12:00 we get, 11:00.
The answer is D
Let t be the start time at which car1 starts. So the distance travelled by car 1 would be d= 54t
Car 2 leaves 2 hours later. The distance travelled by car 1 would be d = 66(t+2).
54t = 66(t+2)
Solving the above should give the time as 11 hours. Adding 11 hours to 12:00 we get, 11:00.
The answer is D
