GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
A wildlife preserve is being planned for 3,000 rhinoceroses. The prese
[#permalink]
15 Nov 2021, 06:23
15 Nov 2021, 06:23
Expert Reply
1
Bookmarks
00:00
Question Stats:
50% (02:00) correct
50% (01:25) wrong based on 2 sessions
Hide Show timer Statistics
A wildlife preserve is being planned for 3,000 rhinoceroses. The preserve is to contain a total of 10,000 acres of watering area, plus 100 acres of grazing area for each rhinoceros. If the number of rhinoceroses is expected to increase by 10 percent, how many thousand acres should the preserve have in order to provide for the increased population?
(A) 340
(B) 330
(C) 320
(D) 310
(E) 300
(A) 340
(B) 330
(C) 320
(D) 310
(E) 300
Re: A wildlife preserve is being planned for 3,000 rhinoceroses. The prese
[#permalink]
24 Nov 2021, 10:42
24 Nov 2021, 10:42
Expert Reply
Total rhinos =3000
increase = 10% =300
total fixed area for watering =10(in thousand acres)
total area for grazing =300(in thousand acres)
additional area required for grazing as the no of rhinos increased for 3000 to 3300=30(in thousand acres)
sum total area =10+300+30=340(in thousand acres)
increase = 10% =300
total fixed area for watering =10(in thousand acres)
total area for grazing =300(in thousand acres)
additional area required for grazing as the no of rhinos increased for 3000 to 3300=30(in thousand acres)
sum total area =10+300+30=340(in thousand acres)
gmatclubot
Re: A wildlife preserve is being planned for 3,000 rhinoceroses. The prese [#permalink]
24 Nov 2021, 10:42
Moderators:
